## Question: There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)

### Approach 1: Recursion

This problem can be converted to the problem of finding the kth element, where k is (A’s length + B’ Length)/2.

If any of the two arrays is empty, then the kth element is the non-empty array’s kth element.

If k == 0, the kth element is the first element of A or B.

For normal cases (all other cases), we need to recursively move the pointer at the pace of half of an array length through the following steps:

1. Calculate the medians m1 and m2 of the input arrays array1[] and array2[] respectively.

2. If m1 and m2 both are equal then we are done, and return m1 (or m2)

3. If m1 > m2, then median is present in one of the below two subarrays:

From first element of array1[] to m1 (array1[][0...m1])

From m2 to last element of array2[] (array2[][m2…n-1])

4. If m2 > m1, then median is present in one of the below two subarrays.

From m1 to last element of array1[] (array1[][m1…n-1])

From first element of array2[] to m2 (array2[][0...m2])

5. Repeat the above process until size of both the subarrays becomes 2.

6. If size of the two arrays is 2 then use below formula to get the median.

(max(array1[], array2[]) + min(array1[], array2[]))/2

We’re done!

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